Thursday, 10 August 2017

Derivation Of (D²/162) - Unit Weight Of Reinforcement steel Formula

Derivation of (D²/162)




Unit Weight of Reinforcement bar Formula.

Weight = Volume * density

Weight = (Area * length) * Density

Weight = (3.14/4*D²*length of Bar * Density of Steel

(Density of steel is 7850kg/m3 and in mm is equal to
(7850/1000*1000*1000)

Weight = (3.14/3 * d²) * 1000 * (7850/1000*1000*1000)
Weight = (d²/1) * (0.00616225/1)

Weight = [d²/ (1/0.00616225)]

Weight = d²/162.2783     make round to (d²/162) = d²/ (1/0.00616225)

Now formula become like this

Weight = d²/162 * (length of bar)

Note: - This formula is only applicable circular shape Bar, Who density is 7850kg/m3.

Here

Dia = mm
Length = m
Weight = kg


For Example:-

Find the weight of bar if dia of bar is 12mm and length of bar is 10 meter?

Solution:-

Length of bar = 10 m
Dia of bar       = 12 mm
Weight of bar =?

Now put the values in formula
Formula = d²/162 * length

Weight = (12)2/162 * 10
Weight = 0.88 * 10
Weight = 8.88 kg


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  Civil Engineering  

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